The mass of a Particle

[cpaca]

Simple enough, what's the mass of a particle? 
CW 1,2, and 3 are terrible sources for this. 
If you want to measure the explosion of the particle when it blows up and such and want to use CW3, use this: https://knucklecracker.com/forums/index.php?topic=25673.0 
I've measured 1 square of land to be .25 square miles, so .5 miles per side [and we can assume Particulate are similar, since 1 particle = 1 land mired] 
Back to the question. 
With land at .25 square miles, .5 by .5, what is the approximate mass of a particle?

[cpaca]

Guess i'm answering this one myself. 
Particles have a setting where they self-destruct after time; i'm using the explosion from that to minimise error from cannons/missiles/etc. 
Testing has shown the explosion goes about 5 land units by 5 land units before dissipating  [may go to 6x6 or even 7x7 if you look at it when it's more translucent] 
At .5 miles per side per land unit [as previously calculated] that puts the land at 2.5 by 2.5 explosion radius, approximately. 
Pi would be used here, since it's a circular explosion, but calculation of that is difficult due to square tiles, circular explosion. Like putting legos into a circle. 
This ends up with a 6.25 square mile explosion [Hello, the size of an omni.] 
Problem comes as to what kind of explosion this 6.25 square mile explosion is. 
TNT is out [no air] 
Nukes are out [no air, no radioactive effects on the HQ] 

Step 2: Get that into energy. 
I'll just be using TNT. 
I also got tired.  Some sources, anyway. 
I gave up. Just ended up using the fireball range of a Nuke landed on the ground for what I wanted [fireball range might be the smallest, but it's ground landing.]
Here's the nuke measuring site http://nuclearsecrecy.com/nukemap/ 
I got that 4390 kilotons of TNT makes the 6.25 square mile fireball 
For what I use later, I need kilograms. 
3982541 kilo-kilograms [or megagrams] of TNT 
3983 gigagrams of TNT 
about 4 teragrams of TNT
This [https://en.wikipedia.org/wiki/TNT_equivalent] gives each teragram 4.184 petajoules. 
4.184 * 4 is 16.736 [round to 17] petajoules of energy 
This [http://www.anycalculator.com/energytomasscalculator.html] transforms 17 petajoules of energy into 189.2 grams of mass  [gotta say, that's efficiency for the win since that was 3983 gigagrams of tnt] 
189.2 grams of mass in each particle 
YAAAY 
While i'm here, I have mass and size, now to figure out how many particles would have to be packed into 1 particle's size for  a black hole! 
https://www.windows2universe.org/kids_space/black.html says Earth becomes 0.017 meters [could've used 1.7 centimeters, dangit!] black hole 
Mass of earth = 5.972 x 10^24 kg 
Mass of particle = 189.2 grams 
# of particles to equal Earth mass = 3.15 x 10^25 particles 
But that's for a 1.7 centimeter black hole 
Size of particle = 0.5 miles 
To centimeters = 80,467 centimeters 
80,467 cm. land/1.7 cm. black hole earth = 47333 times as many particles needed 
47333 times as much needed for proper black hole * 3.15 * 10^25 for 'improper' black hole = the 47333 was a rounding error, really = 1.5 * 10^30 particles needed for a 1-particle-large black hole. 
At least I know I won't have to worry about the particle hole becoming a black hole.