Guess i'm answering this one myself.

Particles have a setting where they self-destruct after time; i'm using the explosion from that to minimise error from cannons/missiles/etc.

Testing has shown the explosion goes about 5 land units by 5 land units before dissipating [may go to 6x6 or even 7x7 if you look at it when it's more translucent]

At .5 miles per side per land unit [as previously calculated] that puts the land at 2.5 by 2.5 explosion radius, approximately.

Pi would be used here, since it's a circular explosion, but calculation of that is difficult due to square tiles, circular explosion. Like putting legos into a circle.

This ends up with a 6.25 square mile explosion [Hello, the size of an omni.]

Problem comes as to what kind of explosion this 6.25 square mile explosion is.

TNT is out [no air]

Nukes are out [no air, no radioactive effects on the HQ]

Step 2: Get that into energy.

I'll just be using TNT.

I also got tired. Some sources, anyway.

I gave up. Just ended up using the fireball range of a Nuke landed on the ground for what I wanted [fireball range might be the smallest, but it's ground landing.]

Here's the nuke measuring site

http://nuclearsecrecy.com/nukemap/ I got that 4390 kilotons of TNT makes the 6.25 square mile fireball

For what I use later, I need kilograms.

3982541 kilo-kilograms [or megagrams] of TNT

3983 gigagrams of TNT

about 4 teragrams of TNT

This [https://en.wikipedia.org/wiki/TNT_equivalent] gives each teragram 4.184 petajoules.

4.184 * 4 is 16.736 [round to 17] petajoules of energy

This [http://www.anycalculator.com/energytomasscalculator.html] transforms 17 petajoules of energy into 189.2 grams of mass [gotta say, that's efficiency for the win since that was 3983 gigagrams of tnt]

189.2 grams of mass in each particle

YAAAY

While i'm here, I have mass and size, now to figure out how many particles would have to be packed into 1 particle's size for a black hole!

https://www.windows2universe.org/kids_space/black.html says Earth becomes 0.017 meters [could've used 1.7 centimeters, dangit!] black hole

Mass of earth = 5.972 x 10^24 kg

Mass of particle = 189.2 grams

# of particles to equal Earth mass = 3.15 x 10^25 particles

But that's for a 1.7 centimeter black hole

Size of particle = 0.5 miles

To centimeters = 80,467 centimeters

80,467 cm. land/1.7 cm. black hole earth = 47333 times as many particles needed

47333 times as much needed for proper black hole * 3.15 * 10^25 for 'improper' black hole = the 47333 was a rounding error, really = 1.5 * 10^30 particles needed for a 1-particle-large black hole.

At least I know I won't have to worry about the particle hole becoming a black hole.